Sunday, 9 August 2015
the position of a 280-g object is given (in meters) by x =5.0t 3 – 8.0t 2 – 44t, where t is in seconds
the position of a 280-g object is given (in meters) by x =5.0t 3 – 8.0t 2 – 44t, where t is in seconds.determine the net rate of work done on this object (a) at t = 2.0 sand (b) at t = 4.0s. (c) what is the average net power output during the interval from t = 0s to t = 2.0s, and in the interval from t =2.0s to 4.0s?
Click here to order this paper @Essaybay.net. The Ultimate Custom Paper Writing Service
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment